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36g^2-1089=0
a = 36; b = 0; c = -1089;
Δ = b2-4ac
Δ = 02-4·36·(-1089)
Δ = 156816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{156816}=396$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-396}{2*36}=\frac{-396}{72} =-5+1/2 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+396}{2*36}=\frac{396}{72} =5+1/2 $
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